Guest
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 Posted: Tue Apr 29, 2008 2:44 am Post subject: [asterisk-users] Newbie Queue: greetings when first joiningq |
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| Quote: | Check the number of calls waiting in the queue, then play the message
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if
| Quote: | more than 0
example code (written in the TBird IDE)
Exten => 100,1,Answer()
Exten => 100,n,Set(NumWaiting=${QUEUE_WAITING_COUNT(${QUEUENAME})})
Exten => 100,n,GotoIf($[${NumWaiting} = 0]?JoinQueue)
Exten => 100,n,PlayBack(MyMessage)
Exten => 100,n(JoinQueue),Queue(MyQueueName)
Exten => 100,n,Hangup()
So, if there are no members in the queue, jump directly to the queue
application, otherwise play the message first.
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Thanks Julian and it certainly works.
I have got another question if I may.
If there is just one agent in the queue and he put on Do-Not-Disturb,
certainly in this case the queue count will be zero but I would still
like Asterisk to play back "Welcome to XYZ, your call is important to us
... please stay on the line", the logic above would fail to play back
the intro message.
I thought about trapping DIALSTATUS but if there is actually no dial
cmd, how can I trap the DND then and play back the message again?
Any thoughts? |
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