zaf at fastmail.com
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 Posted: Tue Oct 11, 2016 3:31 am Post subject: [asterisk-users] AGI: How to break out of AGI when stream_fi |
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On Mon, 10 Oct 2016, at 22:47, Jonathan H wrote:
| Quote: | For reasons best known to myself, I call a python agi (PYST2 - love
it!) which streams a series of very short files in quick succession.
Like this:
escape_digits = str("0")
agi.stream_file(promptFile,escape_digits)
and this is what I see on the AGI debug:
<Local/s@root-00000061;2>AGI Tx >> 200 result=0 endpos=6784
<Local/s@root-00000061;2>AGI Rx << STREAM FILE
/home/DefaultPrompts/en_GB/female/wx/low "0" 0
-- <Local/s@root-00000061;2> Playing
'/home/DefaultPrompts/en_GB/female/wx/low.alaw' (escape_digits=0)
(sample_offset 0) (language 'en_GB')
<Local/s@root-00000061;2>AGI Tx >> 200 result=48 endpos=1440
The FIRST line is a file that finished normally, with result=0, the
LAST line is a file that was interrupted, and receives result=48 from
asterisk.
Yes, zero stops the file playing, but it just goes onto the next file.
So, how do I get that variable? It doesn't become available in python,
and trying to get it via either
agi.env[result']
agi.get_variable('result')
just makes python choke and the AGI quits. That would be fine if it
was a result of result being 48!
I feel like I'm going slightly bonkers here because it's something so
obvious, and yet I've googled so hard over this!
Thanks.
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Hello,
as the docs on stream_file() mention it returns the digit if one was
pressed.
So you might want to try something like:
pressed_digit = agi.stream_file(promptFile,escape_digits)
in you case the raw value 48 is converted to its ascii equivalent so
pressed_digit will have the value 0
--
Lefteris Zafiris
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